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0=x^2-60x-150
We move all terms to the left:
0-(x^2-60x-150)=0
We add all the numbers together, and all the variables
-(x^2-60x-150)=0
We get rid of parentheses
-x^2+60x+150=0
We add all the numbers together, and all the variables
-1x^2+60x+150=0
a = -1; b = 60; c = +150;
Δ = b2-4ac
Δ = 602-4·(-1)·150
Δ = 4200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4200}=\sqrt{100*42}=\sqrt{100}*\sqrt{42}=10\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{42}}{2*-1}=\frac{-60-10\sqrt{42}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{42}}{2*-1}=\frac{-60+10\sqrt{42}}{-2} $
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